At the instant \(t = 0\), vehicle A is travelling due east at a constant speed of \(20\) m/s from the origin \(O\) and vehicle B is travelling due south at a constant speed of \(10\) m/s from point \(P\) that is \(100\) m from \(O\). The position of the two vehicles at \(t = 0\) is shown in the diagram.
Show that, at any time \(t\), the distance between the two vehicles \(D\) m, is given by \(D = 10\sqrt{5(t^2 - 4t + 20)}.\)
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