Given $y = \frac{3}{\sqrt{2x-1}}$, $x \frac{1}{2}$, find \(\frac{\mathrm{d}y}{\mathrm{

Question

Given $y = \frac{3}{\sqrt{2x-1}}$, $x > \frac{1}{2}$, find $\frac{\mathrm{d}y}{\mathrm{d}x}$. Explain why the graph of $y = \frac{3}{\sqrt{2x-1}}$ does not have a stationary point. State whether $y = \frac{3}{\sqrt{2x-1}}$ is an increasing or decreasing function. Explain your answer clearly.

Accepted Answer

$\frac{\mathrm dy}{\mathrm dx}=-\frac3{(2x-1)^{3/2}}$ (a) No stationary point because $\frac{\mathrm dy}{\mathrm dx}\ne0$ (b) Decreasing for $x>\frac12$

Differentiation - Increasing and Decreasing Functions

Differentiation - Increasing and Decreasing Functions

Video Solution:

Solution:

Solution locked