A curve is defined by the parametric equations $x = 2t - 1$, $y = t^{2} + 2$. Show that the equa

Question

A curve is defined by the parametric equations $x = 2t - 1$, $y = t^{2} + 2$. Show that the equation of the tangent to the curve at the point $P(2p - 1, p^{2} + 2)$ is $y = px - p^{2} + p + 2$. Hence, find the equations of the tangents that pass through the point $(-1, -2)$.

Accepted Answer

$y=2x$ and $y=-2x-4$

Techniques of Differentiation - Differentiation of Parametric Equations

Techniques of Differentiation - Differentiation of Parametric Equations

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