Differentiation - Tangents and Normals at a Point

Differentiation - Tangents and Normals at a Point

TGM Original Questions

Find the equations of the tangent and the normal to the curve \(y = x^{3} + x^{2} - 4x - 3\) at the point where \(x = -2\).

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Answer:Tangent: \(y=4x+9\); normal: \(y=-\dfrac14x+\dfrac12\)

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