A curve $C$ is given parametrically by $x = \frac{1}{1 - t^{2}}$, $y = \frac{t}{1 - t^{2}}$. S

Question

A curve $C$ is given parametrically by $x = \frac{1}{1 - t^{2}}$, $y = \frac{t}{1 - t^{2}}$. Show that the equation of the tangent at the point $\left(-\frac{1}{3}, -\frac{2}{3}\right)$ is $4y - 5x = -1$.

Accepted Answer

$4y-5x=-1$

Techniques of Differentiation - Quotient Rule

Techniques of Differentiation - Quotient Rule

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