<p>The diagram below shows part of the graph of the <strong>gradient</strong> function, \(y = f'(x)\).</p>
<div class="content-block"><figure class="question-figure aligncenter" style="text-align: center;"><img src="https://vocwkpgapvksartxhhor.supabase.co/storage/v1/object/sign/question-images/pasted/1777906316471-hvtiw2eod2j.png?token=eyJraWQiOiJiZTM3ZjNhZS05OWM4LTQ5ZGQtYjRiNS1iMTBhYmJhNjY5MWYiLCJhbGciOiJIUzI1NiJ9.eyJ1cmwiOiJxdWVzdGlvbi1pbWFnZXMvcGFzdGVkLzE3Nzc5MDYzMTY0NzEtaHZ0aXcyZW9kMmoucG5nIiwic2NvcGUiOiJkb3dubG9hZCIsImlhdCI6MTc5MzU1MzQ3OSwiZXhwIjoxNzkzNTUzNzc5fQ.eEHkPQbMi9GuNp_ifJ38dK-n4j3C1NyUP6d3NrhYK1k" style="max-width: min(250px, 100%); height: auto; display: block;" class="aligncenter custom-width" /></figure></div>
<ol class="abc-list"><li><div class="list-item-paragraph">On the grid below, sketch a graph of \(y = f''(x)\), clearly indicating the \(x\)-intercept.<span class="inline-marks">[2]</span></div><div class="content-block list-item-image" style="text-align: center;"><img src="https://vocwkpgapvksartxhhor.supabase.co/storage/v1/object/sign/question-images/pasted/1777906425383-whlir68swo.png?token=eyJraWQiOiJiZTM3ZjNhZS05OWM4LTQ5ZGQtYjRiNS1iMTBhYmJhNjY5MWYiLCJhbGciOiJIUzI1NiJ9.eyJ1cmwiOiJxdWVzdGlvbi1pbWFnZXMvcGFzdGVkLzE3Nzc5MDY0MjUzODMtd2hsaXI2OHN3by5wbmciLCJzY29wZSI6ImRvd25sb2FkIiwiaWF0IjoxNzkzNTUzNDc5LCJleHAiOjE3OTM1NTM3Nzl9.POAj60n7iPnZrqQTpz9g3gSKx5z1VPTaFGx9-_rvX38" alt="List item image" class="aligncenter" style="max-width: 100%; height: auto;" /></div></li><li><div class="list-item-paragraph">Complete the table, for the graph of \(y = f(x)\).<span class="inline-marks">[2]</span></div></li></ol>
<div class="content-block content-block--table"><div class="table-container"><table style="table-layout: fixed; width: 360px;"><colgroup><col style="width: 200px;"><col style="width: 160px;"></colgroup><thead><tr><th style="text-align: left; --cell-justify: flex-start"></th><th style="text-align: center; --cell-justify: center"><p>\(x\)-coordinate</p></th></tr></thead><tbody><tr><td style="text-align: center; --cell-justify: center"><p>(i) Maximum point on \(f\)</p></td><td style="text-align: left; --cell-justify: flex-start"></td></tr><tr><td style="text-align: center; --cell-justify: center"><p>(ii) Inflexion point on \(f\)</p></td><td style="text-align: left; --cell-justify: flex-start"></td></tr></tbody></table></div></div>
<ol class="abc-list" start="3"><li><div class="list-item-paragraph">Justify your answer to part (b) (ii).<span class="inline-marks">[2]</span></div></li></ol>

The diagram below shows part of the graph of the **gradient** function, \(y = f'(x)\).

On the grid below, sketch a graph of \(y = f''(x)\), clearly indicating the \(x\)-intercept.

Complete the table, for the graph of \(y = f(x)\).

Mathematics

International Baccalaureate Mathematics: Applications and Interpretation Standard Level

	\(x\)-coordinate
(i) Maximum point on \(f\)
(ii) Inflexion point on \(f\)