Triangle $ABC$ is inscribed in a circle. $AB$ is a diameter and $\angle BAC=42^\circ$. Find \(

Question

Triangle $ABC$ is inscribed in a circle. $AB$ is a diameter and $\angle BAC=42^\circ$. Find $\angle ACB$, giving a reason.[1] Find $\angle ABC$, giving a reason.[2]

Accepted Answer

(a) $90^\circ$ (b) $48^\circ$

Angles in a semicircle

Angles in a semicircle

Solution:

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