In the diagram $AHD$ is a straight line, $BC=CD$, $BH$ is parallel to $CD$ and $H$ is a po

Question

In the diagram $AHD$ is a straight line, $BC=CD$, $BH$ is parallel to $CD$ and $H$ is a point on $AD$. $\angle ABC=125{}^\circ $, $\angle BCD=110{}^\circ $, $\angle CDA=73{}^\circ $ Find, stating all geometrical reasons clearly, $\angle BAD$, $\angle BDH$.

Accepted Answer

(a) $\angle BAD=52^\circ$ (b) $\angle BDH=38^\circ$

Angles in a Quadrilateral with Parallel and Equal Sides

Angles in a Quadrilateral with Parallel and Equal Sides

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