Angle at a harbour from a bearing, and a distance found with the sine rule

A ship leaves a harbour \(H\) and sails due south to a point \(S\). A buoy \(K\) is \(7\) km from \(H\) on a bearing of \(152^\circ\). From \(S\), the bearing of the buoy is \(038^\circ\). The diagram below shows this information.

1. Find the size of angle \(K\hat{H}S\).[1]
2. Find the distance \(KS\).[4]