The vertices $A,B,C,D$, in that order, form a cyclic quadrilateral. Side $BC$ is extended beyond

Question

The vertices $A,B,C,D$, in that order, form a cyclic quadrilateral. Side $BC$ is extended beyond $C$ to $E$. Given $\angle DAB=68^\circ$, find $\angle DCE$, giving a reason.[2]

Accepted Answer

$68^\circ$

An exterior angle of a cyclic quadrilateral

An exterior angle of a cyclic quadrilateral

Solution:

Solution locked