An area model for a fenced pen

An area model for a fenced pen

Secondary 2

A farmer uses \(30\) m of fencing to make three sides of a rectangular pen against a long wall. The two sides at right angles to the wall are each \(x\) m long.

  1. Show that the area of the pen, \(A\text{ m}^2\), is given by \(A=x(30-2x)\).
  2. Find the values of \(x\) for which the area is \(100\text{ m}^2\).
  3. Explain why \(x\) must lie between \(0\) and \(15\).
  4. Use the symmetry of the graph of \(A\) against \(x\) to find the greatest possible area.

Solution:

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Answer:(a) Shown (b) \(x=5\) or \(x=10\) (c) Both lengths \(x\) and \(30-2x\) must be positive (d) \(112.5\text{ m}^2\) (at \(x=7.5\))

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