In cyclic quadrilateral $ABCD$, $\angle DAB=(2x+10)^\circ$ and $\angle BCD=(3x-5)^\circ$. The

Question

In cyclic quadrilateral $ABCD$, $\angle DAB=(2x+10)^\circ$ and $\angle BCD=(3x-5)^\circ$. The diagram labels these angles $p$ and $q$ respectively. Find $x$.[2] Find $\angle DAB$ and $\angle BCD$.[2]

Accepted Answer

(a) $x=35$ (b) $80^\circ$, $100^\circ$

An angle constraint in a cyclic quadrilateral

An angle constraint in a cyclic quadrilateral

Solution:

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