An alternating remainder
An alternating remainder
4 marks
TGM Original
A GP has first term 15 and ratio - 12. Find S_infinity-S_3 and state whether S_3 lies above or below the limiting total.
Solution:
Solution locked
680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.
Create a free account to practise similar questions.
Answer:\(S_\infty-S_3=-\frac54\); \(S_3\) lies above the limit.
Need help? Join our JC Math tuition classes.
Learn more