Finding constants from an expansion
Finding constants from an expansion
IP 1
7 marks
- Expand and simplify \((2x+a)(x-3)\), where \(a\) is a constant.[2]
- It is given that \((2x+a)(x-3)+b=2x^2+5x-7\) for all values of \(x\), where \(b\) is a constant. Find the values of \(a\) and \(b\).[3]
- Hence, without expanding again, factorise \(2x^2+5x-33\).[2]
Solution:
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Answer:(a) \(2x^2+(a-6)x-3a\) (b) \(a=11\), \(b=26\) (c) \((2x+11)(x-3)\)
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