Splitting a fraction into two simpler fractions
Splitting a fraction into two simpler fractions
IP 2
7 marks
It is given that \(\dfrac{5x+1}{(x+1)(x-1)}=\dfrac{A}{x+1}+\dfrac{B}{x-1}\) for all values of \(x\) other than \(-1\) and \(1\), where \(A\) and \(B\) are constants.
- Find the values of \(A\) and \(B\).[4]
- Hence solve the equation \(\dfrac{5x+1}{x^2-1}=\dfrac{2}{x+1}+6\).[3]
Solution:
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Answer:(a) \(A=2\), \(B=3\) (b) \(x=\dfrac{3}{2}\)
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