Rearranging powers and reciprocals
Rearranging powers and reciprocals
Secondary 2
3 marks
TGM Original Questions
Make \(d\) the subject of \(b=\dfrac{kd^3-e}{3}\).[3]
Assume \(k\ne0\).
Solution:
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Answer:\(d=\sqrt[3]{\dfrac{3b+e}{k}}\)
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