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Comparing plant prices

Comparing plant prices

Secondary 2
12 marks
TGM Original Questions

Optional extension

A rose and an orchid together cost \(\$24\). A gardener buys orchids for \(\$48\). If she buys roses instead and spends \(\$72\), she gets two more plants. Let an orchid cost \($p\).

  1. Write the number of orchids.[2]
  2. Write the number of roses.[2]
  3. Form an equation and show that \(p^2+36p-576=0\).[2]
  4. Solve for \(p\).[2]
  5. Explain the rejected root.[2]
  6. Find the number of roses.[2]

Solution:

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Answer:(a) \(\dfrac{48}{p}\) (b) \(\dfrac{72}{24-p}\) (d) \(p=12\) (e) reject \(-48\) because a price is positive (f) \(6\) roses. (c) \(p^2+36p-576=0\) (shown).

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