Rearranging a formula

Rearranging a formula

Secondary 2
5 marks
TGM Original Questions

\(h=\sqrt[3]{\dfrac{3h}{p^2-2x}}\), where \(h\ne0\) and \(p>0\).

  1. Find \(x\) when \(h=-1\) and \(p=2\).[2]
  2. Express \(p\) in terms of \(h\) and \(x\).[3]

Solution:

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Answer:(a) \(\frac12\). (b) \(p=\sqrt{2x+\frac3{h^2}}\).

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