Factorise $6{{x}^{2}}+19x-36$. Hence, solve $\frac{3x-1}{3x-4}-\frac{13}{6{{x}^{2}}+19x-36}=2$.

Question

Accepted Answer

(a) $(3x-4)(2x+9)$ (b) ${x = 2}$ or ${x = -\frac{25}{6} = -4\frac{1}{6}}$

Algebra: Factorising and Using the Result to Solve an Equation