ACJC Tutorial 7 Q5
ACJC Tutorial 7 Q5
Tutorial
It is given that \(y=\frac{2{{x}^{2}}+1}{x-2},\,x\in \mathbb{R},\,x\ne 2\).
Without using a calculator, find the exact set of values that \(y\) can take.
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Answer:\(y\leq8-6\sqrt2\) or \(y\geq8+6\sqrt2\)
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