ACJC TUTORIAL 22 Q9
ACJC TUTORIAL 22 Q9
Tutorial
For \(0 < b < 1\), evaluate the following integral in terms of \(b\):
- \(\displaystyle\displaystyle \displaystyle\int_{0}^{1}{x}\left| x-b \right|\,\mathrm{d}x\)
- \(\displaystyle\displaystyle \displaystyle\int_{-1}^{0}{x}\left| x-b \right|\,\mathrm{d}x\)
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Answer:\(\dfrac{1}{3}b^3 - \dfrac{1}{2}b + \dfrac{1}{3}\); \(-\left(\dfrac{1}{2}b + \dfrac{1}{3}\right)\)
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