ACJC Hypothesis Testing Tutorial Q11

ACJC Hypothesis Testing Tutorial Q11

Tutorial

The random variable \(X\) has a normal distribution with mean \(\mu \) (unknown) and variance \({{\sigma }^{2}}\) (known). To test the null hypothesis \({{H}_{0}}:\mu ={{\mu }_{0}}\), a random sample of \(n\) observations of \(X\) is taken, and the sample mean is \(\bar{x}\).

Find in terms of \({{\mu }_{0}}\), \(\sigma \) and \(n\), the set of values of \(\bar{x}\) which will result in each of the following:

  1. \({{H}_{0}}\) being rejected in favour of \({{H}_{1}}:\mu \ne {{\mu }_{0}}\) at the \(5%\) level of significance;
  2. not being rejected in favour of \({{H}_{1}}:\mu <{{\mu }_{0}}\) at the \(1%\) level of significance.

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs a course plan.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.

Answer:\(\bar{x} \leq \mu_0 - \frac{1.96\sigma}{\sqrt{n}}\) or \(\bar{x} \geq \mu_0 + \frac{1.96\sigma}{\sqrt{n}}\); \(\bar{x} > \mu_0 - \frac{2.33\sigma}{\sqrt{n}}\)

Need help? Join our JC Math tuition classes.

Learn more