Optional extension The distance $d$ metres of an object above the ground varies directly with \((t

Question

Optional extension The distance $d$ metres of an object above the ground varies directly with $(t-18)^2$, where $t$ is seconds. Given $d=45$ at $t=3$, find

Accepted Answer

(i) $d=\dfrac15(t-18)^2$ (ii) $18$ s

Height above the ground

Height above the ground

Solution:

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