A sine ratio in the second quadrant
A sine ratio in the second quadrant
5 marks
TGM Original
Given sintheta=5/13 and 90
Solution:
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Answer:\(\sin\theta=\dfrac{5}{13}\); \(\cos\theta=- \dfrac{12}{13}\); \(\tan\theta=- \dfrac{5}{12}\); \(\operatorname{cosec}\theta=\dfrac{13}{5}\); \(\sec\theta=- \dfrac{13}{12}\); \(\cot\theta=- \dfrac{12}{5}\).
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