A curve has equation $y=(x-2)^2+3$. State the turning point and the equation of the axis of symmet

Question

A curve has equation $y=(x-2)^2+3$. State the turning point and the equation of the axis of symmetry.[2] Sketch the curve on the axes, showing its y-intercept and turning point.[1] Explain why the line $y=2$ does not intersect the curve.[1]

Accepted Answer

(a) $(2,3)$, $x=2$ (b) Upward curve through $(0,7)$ (c) $y\ge3$

A quadratic minimum

A quadratic minimum

Solution:

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