Triangles $ABC$ and $PQR$ satisfy $\angle BAC=\angle QPR=40^\circ$, \(\angle ACB=\angle PRQ=75

Question

Triangles $ABC$ and $PQR$ satisfy $\angle BAC=\angle QPR=40^\circ$, $\angle ACB=\angle PRQ=75^\circ$ and $AB=PQ=6\text{ cm}$. Prove that $\triangle ABC\equiv\triangle PQR$.[2] Find $\angle PQR$.[1]

Accepted Answer

(a) AAS (b) $65^\circ$

A non-included corresponding side

A non-included corresponding side

Solution:

Solution locked