A horizontal chord and its bisector

A horizontal chord and its bisector

Secondary 3
6 marks
TGM Original Questions

The line \(y=1\) meets the circle \((x-1)^2+(y+2)^2=25\) at \(A\) and \(B\).

  1. Find the coordinates of \(A\) and \(B\), and the length of \(AB\).[4]
  2. Find the equation of the perpendicular bisector of \(AB\).[2]

Solution:

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Answer:(a) \((-3,1)\), \((5,1)\); length \(8\). (b) \(x=1\).

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