Sketch y=(x+1)2(x-2) and y=|(x+1)2(x-2)| on separate axes. Label all axis intersections, indicate crossing or touching at each zero, and state which portions reflect.
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Answer:Horizontal intercepts \((-1,0)\), \((2,0)\); vertical intercept \((0,-2)\). Touches at \(-1\), crosses at \(2\); negative for \(x<2\), except the zero at \(-1\). Reflect exactly these negative portions. Modulus vertical intercept \((0,2)\). Every zero is a touching point of the modulus graph.