A delayed departure
A delayed departure
5 marks
TGM Original
Time t is measured in hours after 12:00. A boat remains at (10,2) km until 13:30, then moves with constant velocity -4 i+6 j km h-1. Give its position vector for t 1.5 and its position at 15:00.
Solution:
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Answer:\(\mathbf r(t)=\begin{pmatrix}10\\ 2\end{pmatrix}+\left(t-\frac32\right)\begin{pmatrix}-4\\ 6\end{pmatrix}\text{ km};\quad(4,11)\text{ km}\)
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