For a biased die, $P(1)=0.15$ and $P(6)=0.25$. Scores 2, 3, 4 and 5 are equally likely. The roll

Question

For a biased die, $P(1)=0.15$ and $P(6)=0.25$. Scores 2, 3, 4 and 5 are equally likely. The rolls are independent and the probabilities remain unchanged from one roll to the next.

Accepted Answer

(a) $0.45$ (b) no—probabilities are unchanged and 6 is most likely.

A biased die and the gambler’s fallacy

A biased die and the gambler’s fallacy

Solution:

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