The target form
Rewrite the general term as a difference of shifted terms, for example \(u_r=f(r)-f(r+1)\). Then
\[\sum_{r=1}^{n}[f(r)-f(r+1)]=f(1)-f(n+1).\]
Why it works
The middle terms cancel when the first few and last few terms are written out. A shift of two leaves two terms at the front and two at the end.
Reliable routine
A term tending to zero is necessary for convergence, but it is not enough. The partial sums must approach a finite limit.
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