In the diagram, $BC\parallel QP$, so $\triangle ABC\sim\triangle AQP$. Given $BC=5$ cm, \(AC=3

Question

In the diagram, $BC\parallel QP$, so $\triangle ABC\sim\triangle AQP$. Given $BC=5$ cm, $AC=3$ cm, $AP=6$ cm and $AQ=10$ cm, find $AB$. $A$ $B$ $C$ $Q$ $P$ $3$ $6$ $5$ $10$

Accepted Answer

$AB=5$ cm.

Length from nested similar triangles

Length from nested similar triangles

Solution:

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