Core stretch Triangle $ABC$ is right-angled at $A$, and $M$ lies on $AB$. Given $AM=12$ cm

Question

Core stretch Triangle $ABC$ is right-angled at $A$, and $M$ lies on $AB$. Given $AM=12$ cm, $AC=BM$, and $\tan\angle ABC=3/5$, find $12$ $BM=AC$ $AC$ $A$ $M$ $B$ $C$

Accepted Answer

(a) $18$ cm (b) $162\text{ cm}^2$ (c) $3\sqrt{13}/13$.

An internal point and an exact sine value

An internal point and an exact sine value

Solution:

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