Make $f$ the subject of $v=\dfrac{5s(f^2-u)}{f^2}$. Assume $5s\ne v$ and \(\dfrac{5su}{5s-v}0

Question

Make $f$ the subject of $v=\dfrac{5s(f^2-u)}{f^2}$. Assume $5s\ne v$ and $\dfrac{5su}{5s-v}>0$.

Accepted Answer

$f=\pm\sqrt{\dfrac{5su}{5s-v}}$

Changing the subject in rational formulae