Make the variable in square brackets the subject: $V=\dfrac{h^2+k^2}{3h}$ [$k$].[3]

Assume $h\ne0$ and $3hV-h^2\ge0$.

Question

Make the variable in square brackets the subject: $V=\dfrac{h^2+k^2}{3h}$ [$k$]. Assume $h\ne0$ and $3hV-h^2\ge0$.

Accepted Answer

$k=\pm\sqrt{3hV-h^2}$

Changing the subject of formulae