Hotel rooms allocated without replacement

Hotel rooms allocated without replacement

Secondary 2
4 marks
TGM Original Questions

Core stretch

Each unallocated room is equally likely to be assigned to the next guest.

Hotel rooms are numbered 1 to 30 and allocated without replacement.

  1. Find the probability that the first guest receives a room number
    1. not more than 18,[1]
    2. prime.[1]
  2. A prime-numbered room has been allocated to the first guest. From the 29 remaining rooms, find the probability that the second guest also receives a prime-numbered room.[2]

Solution:

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Answer:(a)(i) \(\frac{3}{5}\) (ii) \(\frac{1}{3}\) (b) \(\frac{9}{29}\).

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