2026 YTSS P1 Q20

\(P,Q,R,S\) are points on horizontal grounds.

\(PQ=18\text{ km},QR=10\text{ km}\) and the bearing of \(P\) from \(Q\) is \(038^\circ\).

\(S\) is to the East of \(Q\).

The area of triangle \(SQR\) is half the area of triangle \(SQP\).

1. Find the angle \(SQR\).[4]
2. Calculate the distance \(PR\).[3]