Two sets \(P\) and \(Q\) are such that \(P\subset Q\).
Fill in each box with one of the following:
\(\varnothing\qquad\cup\qquad\cap\qquad P\qquad Q\qquad P^{\prime}\qquad Q^{\prime}\)
\((P\cap Q)\ \boxed{\phantom{\cup}}\ (P^{\prime}\cap Q)=Q\)[1]
\((P^{\prime}\cup Q)\prime=\boxed{\phantom{\varnothing}}\)[1]
Andy claims “\(A\cap B=\varnothing\), then \(A\subset B^{\prime}\).”
Do you agree with Andy? Justify your answer with explanation.[1]