2026 TPSS P2 Q6

2026 TPSS P2 Q6

Secondary 4
7 marks

\(OAC\) is a triangle and \(B\) is a point on \(OC\).

\(\overrightarrow{OA}=\mathbf a\), \(\overrightarrow{OB}=2\mathbf b\) and \(OB:BC=2:3\).

\(X\) is the point on \(AB\) such that \(AX:XB=1:2\).

  1. Express \(\overrightarrow{AC}\), as simply as possible, in terms of \(\mathbf a\) and \(\mathbf b\).[1]
  2. Express \(\overrightarrow{XB}\), as simply as possible, in terms of \(\mathbf a\) and \(\mathbf b\).[2]
  3. \(Y\) is the point on \(BC\) such that \(\overrightarrow{XY}\) is parallel to \(\overrightarrow{AC}\). Find \(\overrightarrow{XY}\), in terms of \(\mathbf a\) and \(\mathbf b\).[2]
  4. Find the ratio of the area of triangle \(AOB\) : area of triangle \(ABC\).[1]
  5. Find the value of \(\dfrac{\text{area of triangle}\hspace{0.5em}BXY}{\text{area of trapezium}\hspace{0.5em}AXYC}\).[1]

Solution:

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Answer:(a) \(-\mathbf a+5\mathbf b\) (b) \(-\dfrac23\mathbf a+\dfrac43\mathbf b\) (c) \(-\dfrac23\mathbf a+\dfrac{10}3\mathbf b\) (d) \(2:3\) (e) \(\dfrac45\)

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