2026 TPSS P1 Q3

2026 TPSS P1 Q3

Secondary 4
6 marks

Simplify the following.

    1. \(\left(\dfrac{a^{-15}}{8b^{12}}\right)^{\frac13}\)[2]
    2. \(\dfrac{4x^2}{y}\div\dfrac{20x}{y^3}\)[2]
  2. Given that \(5^{x-4}\times125^x=1\), find the value of \(x\).[2]

Solution:

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Answer:(a)(i) \(\dfrac1{2a^5b^4}\) (ii) \(\dfrac{xy^2}{5}\) (b) \(x=1\)

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