2026 TKGS WA2 Q4

2026 TKGS WA2 Q4

Secondary 4
9 marks

The equation of a curve is \(y=ax+\dfrac bx-1\), where \(a\) and \(b\) are constants.

The normal to the curve at the point \(S(1,3)\) is parallel to the line \(x+2y=10\). This normal meets the curve again at point \(T\).

  1. Show that \(a=3\) and \(b=1\).[5]
  2. Find the coordinates of point \(T\).[4]

Solution:

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Answer:(a) \(a=3,b=1\). (b) \(T=\left(\dfrac27,\dfrac{47}{14}\right)\).

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