2026 RSS P1 Q25

2026 RSS P1 Q25

Secondary 4
8 marks

\(OAB\) is a triangle.

\(\overrightarrow{OA}=\mathbf a\) and \(\overrightarrow{OB}=\mathbf b\).

\(C\) is the point on \(AB\) such that \(AC:CB=3:1\).

\(D\) is the point on \(OB\) such that \(OD:DB=3:4\).

  1. Find, in terms of \(\mathbf a\) and \(\mathbf b\),
    1. \(\overrightarrow{AB}\),[1]
    2. \(\overrightarrow{OC}\),[2]
    3. \(\overrightarrow{OD}\).[1]
  2. \(Q\) is a point on \(OC\) such that \(\overrightarrow{OQ}=\dfrac18\mathbf a+\dfrac38\mathbf b\).
    1. Show that \(A\), \(Q\) and \(D\) are collinear.[3]
    2. Find the ratio of the area of triangle \(OAQ\) to the area of triangle \(ODQ\).[1]

Solution:

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Answer:(a)(i) \(\mathbf b-\mathbf a\) (ii) \(\dfrac14\mathbf a+\dfrac34\mathbf b\) (iii) \(\dfrac37\mathbf b\) (b)(i) \(\overrightarrow{AQ}=\dfrac78\overrightarrow{AD}\), common point \(A\) (shown) (ii) \(7:1\)

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