The sequence \(u_1,u_2,u_3,\ldots\) is defined by \(u_1=4\) and \(u_{n+1}=-\frac13u_n+2\), for \(n\geq1\).
Write down the value of \(u_6\).[1]
Given that as \(n\to\infty\), \(u_n\to l\), find the exact value of \(l\) using an algebraic method.[2]
Using the result \(\displaystyle\sum_{r=1}^{n}r^2=\frac n6(n+1)(2n+1)\), find \(\displaystyle\sum_{r=0}^{n}(n+r)(r+1)\), giving your answer in terms of \(n\), in fully factorised form.[3]
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