\(P\), \(Q\) and \(R\) are three points on horizontal ground.
\(PQ=100\text{ m}\) and the bearing of \(P\) from \(Q\) is \(252^\circ\).
\(PR=40\text{ m}\) and angle \(PRQ=59.8^\circ\).
Sign in to view the step-by-step solution
Need help? Join our JC Math tuition classes.
Learn more