2026 PHS P1 Q23

2026 PHS P1 Q23

Secondary 4
5 marks

\(P\), \(Q\) and \(R\) are three points on horizontal ground.

\(PQ=100\text{ m}\) and the bearing of \(P\) from \(Q\) is \(252^\circ\).

\(PR=40\text{ m}\) and angle \(PRQ=59.8^\circ\).

  1. Find the bearing of \(Q\) from \(P\).[1]
  2. A lifeguard stands on top of an 8-metres high watchtower at \(P\).
    A jogger walks along the straight path from \(R\) to \(Q\).
    1. Calculate the shortest distance from \(P\) to \(RQ\).[2]
    2. Calculate the greatest angle of depression from the lifeguard to the jogger.[2]

Solution:

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Answer:(a) \(072^\circ\) (b)(i) \(34.6\text{ m}\) (ii) \(13.0^\circ\)

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