Written as a product of its primes factors, \(72=2^3\times3^2\).
The number \(72\times45\times\dfrac pq\) is a perfect square where \(p\) and \(q\) are prime numbers.
Find the smallest value of \(\dfrac pq\).[2]
Given that the highest common factor of 72 and \(m\) is \(2^2\times3\), write down the two smallest possible value of \(m\).[1]