Back
2026 NORTHBROOKS P2 Q2
Save PDF
2026 NORTHBROOKS P2 Q2
Secondary 4
9 marks
Given that \(\tan A=3\tan B\), show that \(\tan(A-B)=\dfrac{\sin2B}{1+2\sin^2B}\).
[4]
Solve, in terms of \(\pi\), the equation \(\cos2x=\sqrt3\cos x-1\) for \(0\le x\le2\pi\).
[4]
Hence solve, in terms of \(\pi\), \(\cos x=\sqrt3\cos\dfrac{x}{2}-1\) for \(0\le x\le2\pi\).
[1]
Solution:
Solution locked
Sign in to view the step-by-step solution
Sign in to view
A Math Tuition
Similar Questions
Similar questions are unavailable for this question.
Answer:
(a) Identity shown. (b)(i) \(x=\dfrac\pi6,\dfrac\pi2,\dfrac{3\pi}2,\dfrac{11\pi}6\). (ii) \(x=\dfrac\pi3,\pi\).
Need help?
Join our JC Math tuition classes.
Learn more