The equation of a curve $E$ is $x^2+xy+Ay^2+Bx+Cy+9=0$, where $A$, $B$ and $C$ are co

Question

The equation of a curve $E$ is $x^2+xy+Ay^2+Bx+Cy+9=0$, where $A$, $B$ and $C$ are constants. $E$ passes through the point $(-1,1)$. The line $y=-x+6$ is tangent to $E$ at the point where $x=3$. Find the values of $A$, $B$ and $C$.[5]

Accepted Answer

$A=3$, $B=-3$, $C=-15$

2026 NJC Promo Q2

2026 NJC Promo Q2

Solution:

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