In the diagram, \(ABC\) is a triangle. \(D\) is a point on \(AC\) such that \(AB=BD\) and \(ACE\) is a straight line. Angle \(ABD=(2x)^\circ\) and angle \(BCE=(135-\frac12x)^\circ\).
Prove that triangle \(ABC\) is an isosceles triangle.[3]
Sign in to view the step-by-step solution
Need help? Join our JC Math tuition classes.
Learn more