2026 NASS P1 Q13

2026 NASS P1 Q13

Secondary 4
9 marks

A particle is travelling in a straight line. It passes a fixed point \(A\) with a velocity of \(-7\) m/s. Its acceleration, after passing \(A\) is given by \(a=8-2t\) for \(0\le t\le T\). On reaching its maximum speed at time \(T\) seconds, the particle begins to decelerate at a constant rate of \(1.5\) m/s\(^2\) until it comes to a rest at point \(B\).

  1. Show that the particle first came to instantaneous rest when \(t=1\).[3]
  2. Find the maximum velocity attained by the particle and the value of \(T\).[2]
  3. Find the total distance travelled by the particle from \(A\) to \(B\).[4]

Solution:

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Answer:(a) First rest at \(t=1\) s. (b) Maximum velocity \(9\) m/s; \(T=4\) s. (c) \(\dfrac{145}3\) m.

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