2026 MSHS P2 Q1

2026 MSHS P2 Q1

Secondary 4
10 marks
  1. It is given that \(a=\dfrac{2b+c}{b-c}\).
    1. Find \(a\) when \(b=5\) and \(c=-3\).[1]
    2. Rearrange the formula to make \(b\) the subject.[2]
  2. Solve the inequality \(\dfrac{3x-1}{4}-\dfrac{x+2}{3}>1\).[2]
  3. Simplify \(\left(\dfrac{y^4}{36x^{14}}\right)^{-\frac12}\).[2]
  4. Simplify \(\dfrac{4x^2-12ax-5x+15a}{2x^2-18a^2}\).[3]

Solution:

Solution locked

Sign in to view the step-by-step solution

Similar questions are unavailable for this question.
Answer:(a)(i) \(\dfrac78\) (ii) \(b=\dfrac{c(a+1)}{a-2}\) (b) \(x>\dfrac{23}{5}\) (c) \(\dfrac{6|x|^7}{y^2}\), or \(\dfrac{6x^7}{y^2}\) if \(x>0\) (d) \(\dfrac{4x-5}{2(x+3a)}\).

Need help? Join our JC Math tuition classes.

Learn more